Magnitude Flux Equation
Lose again?
A fixed circle of radius 18 cm is placed in a uniform electric field of magnitude 5.1×10 ^ 2 N / C. b) What is the electrical flow through the circle when his face is 40 ° to the field lines? Equation: EA = cos (E) = 5.1×10 ^ 2 A = pi x 18 ^ 2 = 102 angle = 40 degrees (5.1×10 ^ 2) (, 102) (cos 40) = 39.84 But he is wrong. What am I doing wrong?
The normal component is 40 º Esin if stream = EA sin 40 ª = and you have to take counters from the region to have consistent units
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